Diferencia entre revisiones de «Plantilla:PHP/SQL»

DROP TABLE cliente;
DROP TABLE facturas;
 
CREATE TABLE cliente(
dni varchar2(10) PRIMARY KEY,
nombre varchar2(10) DEFAULT 'mi nombre'
);
CREATE TABLE factura(
num NUMBER PRIMARY KEY,
fecha DATE DEFAULT sysdate,
cantidad NUMBER DEFAULT 10,
cliente varchar2(10),
CONSTRAINT cliente_factura FOREIGN KEY (cliente) REFERENCES cliente(dni) ON DELETE SET NULL
);
 
INSERT INTO  cliente (dni) VALUES ( 1);
INSERT INTO  cliente (dni) VALUES ( 2);
INSERT INTO  cliente (dni) VALUES ( 3);
INSERT INTO  cliente (dni) VALUES ( 4);
 
INSERT INTO  factura(num, cliente) VALUES ( 1, 1);
INSERT INTO  factura(num, cliente) VALUES ( 2, 1);
INSERT INTO  factura(num, cliente) VALUES ( 3, 1);
INSERT INTO  factura(num, cliente) VALUES ( 4, 2);
INSERT INTO  factura(num, cliente) VALUES ( 5, 3);
INSERT INTO  factura(num, cliente) VALUES ( 6, 3);
INSERT INTO  factura(num, cliente) VALUES ( 7, 4);
INSERT INTO  factura(num, cliente) VALUES ( 8, 4);

CREATE TABLE EMPLEADO (
dni varchar2(20),
direccion varchar2(15),
nombre varchar2(20) NOT NULL,
telefono NUMBER,
departamento NUMBER,
CONSTRAINT valor_telefono CHECK(telefono > 600000000),
CONSTRAINT clave_ppal_empleados PRIMARY KEY (dni),
CONSTRAINT nom_tel_unico_emp UNIQUE(nombre, telefono)
);
 
CREATE TABLE DEPARTAMENTO(
numero NUMBER,
nombre varchar2(15),
ubicacion varchar2(20) NOT NULL,
director varchar2(20),
CONSTRAINT numero  PRIMARY KEY (numero),
CONSTRAINT director FOREIGN KEY (director) REFERENCES EMPLEADO(dni)
);
 
ALTER TABLE EMPLEADO
ADD CONSTRAINT pertenece FOREIGN KEY (departamento) REFERENCES DEPARTAMENTO(numero);

ALTER TABLE departamento
DROP CONSTRAINT director;
DROP TABLE empleado;
DROP TABLE departamento;

mysql> SELECT *  
       FROM EMPLOYEES 
       WHERE JOB_ID ="ST_CLERK"       
             AND       
             HIRE_DATE>"1997-12-31";

SELECT LAST_NAME, JOB_ID,SALARY, COMMISSION_PCT 
FROM EMPLOYEES
WHERE COMMISSION_PCT IS NOT NULL 
ORDER BY LAST_NAME DESC;

SELECT 'El salario de '||Last_name||
       'va a ser con un incremento del 10% de '||
       round(Salary *1.10) ||
       ' dólares' AS "Nuevo Salario"
FROM EMPLOYEES
WHERE COMMISSION_pCT IS NULL

SELECT last_name, 
       trunc(months_between(sysdate, hire_date)/12) AS "años",
       trunc(MOD(months_between(sysdate, hire_date),12))AS "meses"
FROM employees
ORDER BY hire_date;

SELECT last_name, salary, decode (commission_pct, 
                                                NULL, 'No' ,
                                                'Yes') AS "comisión"
FROM employees

SELECT department_name, location_id,job_id, salary
FROM departments d, employees e
WHERE d.department_id = e.department_id
       AND
       location_id = '&localizacion';

SELECT COUNT(*) 
FROM employees
WHERE last_name LIKE '%n'

SELECT COUNT(*)
FROM employees
WHERE last_name LIKE '%n';
--or
SELECT COUNT(*)
FROM employees
WHERE SUBSTR(last_name, -1) = 'n';

SELECT d.department_id, d.department_name, d.location_id, COUNT(e.employee_id)
FROM  employees e 
      RIGHT OUTER JOIN departments d
 ON
     e.department_id = d.department_id
GROUP BY d.department_id, d.department_name, d.location_id;

SELECT DISTINCT job_id
FROM employees
WHERE department_id IN (10, 20);

SELECT e.job_id, COUNT(e.job_id) FREQUENCY
FROM employees e 
     JOIN departments d
     ON e.department_id = d.department_id
WHERE   d.department_name IN ('Administration', 'Executive')
GROUP BY e.job_id
ORDER BY FREQUENCY DESC;

SELECT last_name, hire_date
FROM  employees
WHERE TO_CHAR(hire_date, 'DD') < 16;

SELECT last_name, salary, TRUNC(salary, -3)/1000
FROM  employees;

SELECT e.last_name, m.last_name manager, m.salary,
j.grade_level
FROM  employees e JOIN employees m
      ON    e.manager_id = m.employee_id
     JOIN job_grades j
     ON   m.salary BETWEEN j.lowest_sal AND j.highest_sal
     AND  m.salary > 15000;

SELECT   d.department_id, d.department_name, COUNT(e1.employee_id) employees,  
         NVL(TO_CHAR(AVG(e1.salary), '99999.99'), 'No average') avg_sal,  
         e2.last_name, e2.salary, e2.job_id
FROM  departments d RIGHT OUTER JOIN employees e1
      ON  d.department_id = e1.department_id
      RIGHT OUTER JOIN employees e2
      ON   d.department_id = e2.department_id
      GROUP BY d.department_id, d.department_name, e2.last_name,
           e2.salary,
           e2.job_id
      ORDER BY d.department_id, employees;

SELECT department_id, MIN(salary)
FROM  employees
GROUP BY department_id
HAVING AVG(salary) = (SELECT MAX(AVG(salary))
                      FROM  employees
                      GROUP BY department_id);

SELECT *
FROM
departments
WHERE   department_id NOT IN(SELECT department_id
                             FROM employees
                             WHERE job_id = 'SA_REP' 
                               AND department_id IS NOT NULL);

SELECT d.department_id, d.department_name, COUNT(*)
FROM
departments d JOIN employees e
ON
d.department_id = e.department_id
GROUP BY d.department_id, d.department_name
HAVING COUNT(*) < 3;

SELECT d.department_id, d.department_name, COUNT(*)
FROM
departments d JOIN employees e
ON
d.department_id = e.department_id
GROUP BY d.department_id, d.department_name
HAVING COUNT(*) = (SELECT MAX(COUNT(*))
FROM
employees
GROUP BY department_id);

SELECT d.department_id, d.department_name, COUNT(*)
FROM
departments d JOIN employees e
ON
d.department_id = e.department_id
GROUP BY d.department_id, d.department_name
HAVING COUNT(*) = (SELECT MIN(COUNT(*))
FROM
employees
GROUP BY department_id);

SELECT e.employee_id, e.last_name, e.department_id, e.salary,
AVG(s.salary)
FROM
employees e JOIN employees s
ON
e.department_id = s.department_id
GROUP BY e.employee_id, e.last_name, e.department_id,
e.salary;

SELECT last_name, TO_CHAR(hire_date, 'DAY') DAY
FROM  employees
WHERE TO_CHAR(hire_date, 'Day') = (SELECT TO_CHAR(hire_date, 'Day')
                                    FROM employees
                                    GROUP BY TO_CHAR(hire_date, 'Day')
                                    HAVING COUNT(*) = (SELECT MAX(COUNT(*))
                                                       FROM    employees
                                                       GROUP BY TO_CHAR(hire_date,'Day')));

SELECT last_name, TO_CHAR(hire_date, 'Month DD') BIRTHDAY
FROM employees
ORDER BY TO_CHAR(hire_date, 'DDD');